(5x+4)(3x^2-20x-7)=0

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Solution for (5x+4)(3x^2-20x-7)=0 equation: 


Simplifying
(5x + 4)(3x2 + -20x + -7) = 0

Reorder the terms:
(4 + 5x)(3x2 + -20x + -7) = 0

Reorder the terms:
(4 + 5x)(-7 + -20x + 3x2) = 0

Multiply (4 + 5x) * (-7 + -20x + 3x2)
(4(-7 + -20x + 3x2) + 5x * (-7 + -20x + 3x2)) = 0
((-7 * 4 + -20x * 4 + 3x2 * 4) + 5x * (-7 + -20x + 3x2)) = 0
((-28 + -80x + 12x2) + 5x * (-7 + -20x + 3x2)) = 0
(-28 + -80x + 12x2 + (-7 * 5x + -20x * 5x + 3x2 * 5x)) = 0
(-28 + -80x + 12x2 + (-35x + -100x2 + 15x3)) = 0

Reorder the terms:
(-28 + -80x + -35x + 12x2 + -100x2 + 15x3) = 0

Combine like terms: -80x + -35x = -115x
(-28 + -115x + 12x2 + -100x2 + 15x3) = 0

Combine like terms: 12x2 + -100x2 = -88x2
(-28 + -115x + -88x2 + 15x3) = 0

Solving
-28 + -115x + -88x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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